So you have to agree that light is a wave that spreads out over large space. i.e., Light is a wave 'for interference', light is a particle 'for photoelectric effect' and compton effect. For this we assume that light consists of photons. But we have to throw away the behaviour of light as a wave while explaining the photoelectric effect. If we assume that light is a wave containing crests and troughs, then only it is possible to explain the constructive and destructive interference. Photo-electric effect and black body radiation tells us that light has a particle form. Interference, diffraction and polarisation experiment, tell us that light is a wave. But a body occupies a particular position in space for a particle the space needed is very small. We know that a wave spreads out and occupies a large region of space. radiations.Ī particle contains some material and is specificd by its mass m, velocity v, momentum p and enengy E. Let us use the word 'light' to represent any one of the e.m. Electromagnetic radiations like X-ray, gamma ray, visible light, infrared etc, are ivaves. A wave is specified by the quantities like frequency v, wavelength λ, amplitude A, intensity I and phase velocity v. A wave does not contain any particle or matter. Can You Agree ?Ī wave is a disturbance produced in a medium. Light is also a Particle that is at a Point". "Light is a Wave It Spreads out over Space. Davisson and Germer experiment qualitative description and discussion of the experiment, polar graph. The wave nature of matter was proposed by. Dual nature of matter particle nanure common in that it passess momentem p = m and kinetic energy K = 1/2 m v 2. tian: particle nature in photoelectric effect and Compton effect. Dual nature of radiation already discussed wave nature in interfenence, diffraction and polariza. Wave particle duality, De Broglie equation, phenomenon of electron diffraction (informative only). The beats produced are shown by the straight line OQ in the graph. Two tuning forks A and B are sounded together. When some wax is put on the prongs of the other one, the beats disappear. Two tuning forks produce 5 beats per second. What is the frequency of A after scraping?ġ0. When the prongs of A are scraped by a file and sounded with B, then 4 beats per second are heard. What is the frequency of the other fork? Ans. On loading the other with a small wax, the number of beats per second becomes 5. Two tuning forks, on sounding together, produce 3 beats per second. What will be the time-interval between two consecutive beats produced by sounding them together? Ans. The frequencies of two sound-sources are 512 and 516 Hz. Determine the possible frequencies of the other fork.ħ. When it is sounded with another tuning fork, 8 beats per second are produced. The period of vibration of a tuning fork is ( 1/288 ) second. This is possible only when the frequency of A while decreasing is moving away from the frequency of B.Īlternate method : It is given n A = 256 Hz, n B = ? and x = 4 bpsĪlso after loading A (i.e. It means that with decrease in frequency of A, the difference in new frequency of A and the frequency of B has increased. It is given that on sounding waxed fork A (fork of frequency 256 Hz) and fork B, number of beats (beat frequency) increases. Suppose two tuning forks are named A and B with frequencies (known), n B = ? (unknown), and beat frequency x = 4 bps.
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